webassign net chegg study l Guide... Pty 101 w17-Cha Doctor of Physical Webassig

Question

webassign net chegg study l Guide... Pty 101 w17-Cha Doctor of Physical Webassign Net In Frequently Asked Q nbox cnzabellaoak. Each cylinder starts out with the total mechanical energy consisting entirely of gravitational potential energy: Emech Mgho where M is the mass of the cylinder. At a height h above the ground, the kinetic energy has increased at the expense of the potential energy, with the total mechanical energy the same, so that Equate the second expression for Emech to its initial value given by the first equation, and use the relation between the rotational and translational speeds of the rolling cylinder to obtain VCM Mg(ho h) which can be rearranged into 2g(ho h) (MR) Next consider the two cases. For a solid cylinder of mass M- M1, the moment of inertia is M.R2 CM so that the final speed at height h is 4g(h m/s. VCM, solid For the hollow cylinder of mass M M2, he moment of inertia is so that the final speed is VCM, hollow g(ho 9,80 m/s 4 m 13 m m/s (B) Which cylinder takes less time to reach the bottom of the ramp At any height h, the results already obtained show that the solid cylinder is moving at a speed 4g(ho h) CM, solid and the speed of the hollow cylinder at that same height is CM, hollow g(ho h) https://moodle.oa Dashboard

Explanation / Answer

part a:

Vcm,solid=sqrt(4*g*(h0-h)/3)=sqrt(4*9.8*(14-13)/3)=3.6148 m/s

Vcm, hollow=sqrt(g*(h0-h))=sqrt(9.8*(14-13))=3.1305 m/s

part b:

as Vcm,hollow > Vcm,solid,

hollow cylinder takes less time to reach bottom.

part C:

Vcm,solid/Vcm,hollow=sqrt(4/3)=1.1547

finalize:

if mass is distributed more distantly, moment of inertia will be higher

and hence final speed will be lesser. (as Icm is in denominator)

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