Pre-lab Physics A) Using an ammeter, measure the current in the circuit. (You ma

Question

Pre-lab Physics

A) Using an ammeter, measure the current in the circuit. (You may reference the laboratory write up and appendix for specifics on wiring voltmeters and ammeters.) Write all values down with appropriate units. Does this simulated circuit demonstrate Ohm’s Law? Explain using both words and calculations

B) Look at the speed of the simulated electrons moving around the circuit loop. This is a simulation of the current since current is defined as q/t. You may change the resistance value by clicking on the resistor and choosing the option "change resistance". Look at the speed of the current as well as your ammeter as you change the resistance. What happens as you increase the resistance? Can Ohm's law explain the change in the current observed? explain.

C) Add a resistor to the circuit in series and set both resistors to 0 ohms. Now, measure the voltage drop across each resistor, record the values. How do these value compare with the battery input voltage? Does this make sense from Ohm's law? explain

D) Now, change the resistance of one resistor to 20 ohms, what changes in the circuit? Is Ohm's law demonstrated in this new circuit for both resistors? Show.

E) Finally, place the resistors in parallel. Repeat measuring the voltage and current for each resistor. What do you find is the same across both resistors? What is different? Is Ohm's law demonstrated in this circuit? How

Explanation / Answer

Part A

current can be measured by ammeter by putting it in series with the resistor.

ohms law state thet potential across resistor is proportional to current. this can be found by changing voltage and measuring current in the ammeter.

Part B

by changing resistance current can be changed.

V = IR

part C

by adding resistance in series resistance of circuit increases

Req = R1+R2

voltage across each resistor

V1 = IR1/(R1+R2)

V2 = IR2/(R1+R2)

for R=0 ohms

V1 = V2 = infinity

Part d

now if one resistance is changed then current changes and voltage across it has finit value. ohms law followd

Part E

in parallel

Req = R1*R2/(R1+R2)

voltage across each resistor is

V = same as supply voltage

current is different in circuit

ohms law can be demonstrated

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