A parallel plate capacitor of capacitance Co has plates of area A with separatio

Question

A parallel plate capacitor of capacitance Co has plates of area A with separation d between them. When it is connected to a battery of voltage VQ, it has charge of magnitude QQ on its plates. It is then disconnected from the battery and the space between the plates is filled with a material of dielectric constant 3. After the dielectric is added, the magnitudes of the charge on the plates and the potential difference between them are a.1/3Qo, 1/3Vo b.Qrj, 1/3Vo c. Qo, Vo d.Qo,3V0 e. 3Qo, VQ A parallel plate capacitor is charged to voltage Fand then disconnected from the battery. Leopold says that the voltage will decrease if the plates are pulled apart. Gerhardt says that the voltage will remain the same. Which one, if either, is correct, and why? a. Gerhardt, because the maximum voltage is determined by the battery b. Gerhardt, because the charge per unit area on the plates does not change c. Leopold, because charge is transferred from one plate to the other when the plates are separated d. Leopold, because the force each plate exerts on the other decreases when the plates are pulled apart e. Neither, because the voltage increases when the plates are pulled apart

Explanation / Answer

question 1b

the correct part is

e. Neither, because the voltage increases when the plates are pulled apart

beacuse

when the distance increase the capacitance will decrease

C = e0 * A / d

and then

Q = C * V

so when the capacitance decrease the voltage will increase

so therefore when the distance between the plates will increase the voltage will also increase

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