A positive charge of magnitude Q_1 = 65 nC is located at the origin. A negative

Question

A positive charge of magnitude Q_1 = 65 nC is located at the origin. A negative charge Q_2 = -7.5 nC is located on the positive x-axis at x = 16 cm from the origin. The point P is located y = 6.5 cm above charge Q_2. Calculate the x-component of the electric field at point P due to charge Q_1. Write your answer in units of N/C. Calculate the y-component of the electric field at point P due to charge Q_1. Write your answer in units of N/C. Calculate the y-component of the electric field at point P due to the Charge Q_2. Write your answer in units of N/C. Calculate the y-component of the electric field at point P due to both charges. Write your answer in units of N/C. Calculate the magnitude of the electric field at point P due to both charges. Write your answer in units of N/C. Calculate the angle in degrees of the electric field at point P relative to the positive x-axis.

Explanation / Answer

y component of the electric field at P due to Q2 is
Ey2= E2 sin 90

    = (kQ2/r2^2)1
    = 9*10^9*(-7.5*10^-9)/(0.065)^2
    = -15976.33 N/C

Ey1 = E1 sin 22.10
    = k*Q1/(r^2)* sin 22.10
    = (9*10^9*(6.5*10^-9)/(0.1727)^2)sin22.10
    = 737.93 N/C

I Ey I = sqrt((-15976.33)^2+(737.93)^2)= -15993 .34 N/C

Ey = 15976.33+737.93 = -15238.4 N/C

angle is tan theta = Ey/Ex
               theta =arc tan (Ey/Ex)

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