A load of bricks with mass m1 = 15.8 kg hangs from one end of a rope that passes

Question

A load of bricks with mass m1 = 15.8 kg hangs from one end of a rope that passes over a small, frictionless pulley. A counterweight of mass m2 = 28.4 kg is suspended from the other end of the rope, as shown in the figure. (Figure 1) The system is released from rest. Use g = 9.80 m/s2 for the magnitude of the acceleration due to gravity.Part A
What is the magnitude of the upward acceleration of the load of bricks?

  m/s2  

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Part B
What is the tension in the rope while the load is moving?

  N  

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Explanation / Answer

Here ,

m1 = 15.8 Kg

m2 = 28.4 Kg

a) let the magnitude of accleration is a

Using second law of motion

a = (m2 * g - m1 * g)/(m1 + m2)

a = (28.4 - 15.8)* 9.8/(28.4 + 15.8)

a = 2.79 m/s^2

the magnitude of upward acceleration of the load of bricks is 2.79 m/s^2

part B)

let the tension in the rope is T

for the mass m1

Using second law of motion

T - m1 * g = m1 * a

T - 15.8 * 9.8 = 15.8 * 2.79

T = 199 N

the tension in the rope while the load is moving is 199 N

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