A lithium nucleus(3 protons 4 neutrons) with a mass of 11.7*10^-27kg accelerates

Question

A lithium nucleus(3 protons 4 neutrons) with a mass of 11.7*10^-27kg accelerates to the right due to electric forces. The magnitude of acceleration is 3*10^13m/s^2. a) What is the magnitude of the electric force that the lithium experiences? b) What is the magnitude of electric field that acts on the lithium nucleus? c) Where would an electron need to be located in order to produce this electric field at the location of the lithium? (that is, specify the relative position vector between the electron and the lithium)

Explanation / Answer

( a)

Magnitude of electric force:

F = ma

F = ( 11.7 e-27 kg ) ( 3 e13 m/s^2)

F = 3.51e-13 N

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( b )

Expression for electric force:

F = q E

Rearrange for electic field at E

E = F/ q

E = ( 3.51e-13 N ) / ( 3 x 1.6e-19 C )

E = 7.31e+5 N /C

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Expression for field due to point charge

E = k q / r^2

7.31e+5 N /C = ( 9 e+9 ) ( 1.6e-19 C ) / r^2

Solve for r

r = 4.437 e -8 m

T

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