Problem 23.89 An alpha particle with kinetic energy 15.0 MeV makes a collision w

Question

Problem 23.89 An alpha particle with kinetic energy 15.0 MeV makes a collision with lead nucleus, but it is not "aimed" at the center of the lead nucleus, and has an initial nonzero angular momentum (with respect to the stationary lead nucleus) of magnitude L pob, where po is the magnitude of the initial momentum of the alpha particle and b 1.40x10-12 m (Assume that the lead nucleus remains stationary and that it may be treated as a point charge. The atomic number of lead is 82. The alpha particle is a helium nucleus, with atomic number 2.) Part B Repeat for b 13 m. r 1.48x10 m Submit My Answers Give Up Correct Part C Repeat for b 1.00x10-14 m. 2.36 10 14 Submit My Answers Give U incorrect; Try Again; 5 attempts remaining

Explanation / Answer

part C) velocity of alpha partcle = sqrt(2*2.4*10-12/6.64424* 10-27)

                                                   = 2.687*107 m/sec

              Intitial angular momentum = 6.64424* 10-27*2.687*107*1.00*10-14

                                                                                    = 17.84 *10-34 kg*m2/s

           => r = (17.84 *10-34) /(6.64424* 10-27*2.54*107)

                      = 1.057 * 10-14    m

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