Two point charges q1=+2.50nC and q2=6.50nC are 0.100 m apart. Point A is midway
ID: 1586995 • Letter: T
Question
Two point charges q1=+2.50nC and q2=6.50nC are 0.100 m apart. Point A is midway between them; point B is 0.080 m from q1 and 0.060 m from q2. (See (Figure 1) .) Take the electric potential to be zero at infinity.
Find the potential at point A.
Express your answer in volts to three significant figures.
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Part B
Find the potential at point B.
Express your answer in volts to three significant figures.
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Part C
Find the work done by the electric field on a charge of 2.60 nC that travels from point B to point A.
Express your answer in joules to two significant figures.
V = VExplanation / Answer
A) Potential at point A, VA = k*q1/d1 + k*q2/d2
= 9*10^9*2.5*10^-9/0.05 + 9*10^9*(-6.5*10^-9)/0.05
= -720 volts
B) Potential at point A, VA = k*q1/d1 + k*q2/d2
= 9*10^9*2.5*10^-9/0.08 + 9*10^9*(-6.5*10^-9)/0.06
= -693.75 volts
C) Workdone(B to A) = (VB - VA)*q
= (-693.75 - (-720))*2.6*10^-9
= 6.825*10^-8 J
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