Use the following values for mass and charge: an electron has mass m e = 9.11×10

Question

Use the following values for mass and charge: an electron has mass me = 9.11×10-31 kg and charge -e, a proton has mass mp = 1.67×10-27 kg and charge +e, an alpha particle has mass malpha = 6.65×10-27 kg and charge +2e, where e = 1.60×10-19 C. An electron is released from rest in a vacuum between two flat, parallel metal plates that are 14.0 cm apart and are maintained at a constant electric potential difference of 740 Volts. If the electron is released at the negative plate, what is its speed just before it strikes the positive plate?

What is the kinetic energy of the electron in units of eV?

Explanation / Answer

Using Conservation of Energy

The Potential of the electron at release(Uf-Ui) = kinetic at the upper plate(K.E.f-K.Ei)

qV = 1/2*mv2

v = (2*V*q/m)1/2

= (2*740*1.60x10-19/9.11x10-31)1/2

= 1.61x107 m/s

E from qV = 740eV

K = 1/2*m*v^2 = 1/2*9.11x10-31*(1.61x107)2 = 1.18x10-16J or 740 eV

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