Part A Determine magnitude of the electric field at the point P shown in the fig

Question

Part A

Determine magnitude of the electric field at the point P shown in the figure(Figure 1) . The two charges are separated by a distance of 2a. Point P is on the perpendicular bisector of the line joining the charges, a distance x from the midpoint between them.

Express your answer in terms of Q, x, a, and k.

E=???

Part B

Determine the direction of the electric field. Assume that the positive x and y axes are directed to the right and upward respectively.

A - in the negative x direction

B - in the positive x direction

C - in the positive y direction

D - in the negative y direction

Explanation / Answer

The components of the Electric field along Y axes gets cancelled because of symmetry

Only the X componentsw gets added up, since both will be along -X axis

E = E1x+E2x

Here the distance between charge and point is sqrt(a^2+r^2)

E = E1x+E2x

E = k Q/(a^2+r^2)+k Q/(a^2+r^2)

E = 2k Q/(a^2+r^2)

DIRECTION is ALONG negative X direction

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