6.8/10 points I Prev us Answers SerCP8 20.P 002 Find the flux of Earth\'s magnet

Question

6.8/10 points I Prev us Answers SerCP8 20.P 002 Find the flux of Earth's magnetic field of magnitude 5.00 × 10-5 T through a square loop of area 10.0 cm2 for the following: (a) when the field is perpendicular to the plane of the loop 5.00e-m b) when the field makes a 50.0° angle with the normal to the plane of the loop 3 09e-9 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. T·m2 -I (c) when the field makes a 90.0o angle with the normal to the plane Need Help?ReadItTalk to Tuter

Explanation / Answer

here,

magnetic feild , B = 5 * 10^-5 T

area , A = 10 cm^2 = 10^-3 m^2

b)

theta = 50 degree

the magnitude of Earth's magnetic feild , phi = B * A * sin(theta)

phi = 5 * 10^-5 * 10^-3 * sin(50) T.m^2

phi = 3.83 * 10^-8 T.m^2

the magnitude of Earth's magnetic feild is 3.83 * 10^-8 T.m^2

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