Question 1 and 2 Question 1 R: Rs R: R4 The figure shows a circuit with a batter

Question

Question 1 and 2 Question 1 R: Rs R: R4 The figure shows a circuit with a battery and five resistors. What is the current through and the potential difference across each resistor? RI-8.00 . R2-6.00 , R3-8.00 , R4-3.00 , RS _ 7.00 , and v-37.0 v. current through R1: current through Current through RS Current through R4 current through RS: Potential difference across R1 Potential difference across R2 Potential difference across Ry Potential difference across R Potential difference across Rs Question 2 A 12.2 F capacitor initially charged to 42.5 pC is discharged through a 1.85 resistor. How long does it take to reduce the capacitor's charge to 21.2 ? Answer:

Explanation / Answer

from the given data

R1 = 8 ohm

R2 = 6 ohm

R3 = 8 ohm

R4 = 3 ohm

R5 = 7 ohm

V = 37 V

hence

Reff = R1 + R5*(R2 + R3*R4/(R3 + R4))/(R5 +(R2 + R3*R4/(R3 + R4)) )

Reff= 8 + 7(6 + 24/11)/(7 + (6 + 24/11)) = 11.772455 ohm

hence

current through R1, i1 = V/Reff

i1 = 3.1429298 A

potential difference across R1 = V1 = R1*i1 = 25.14343 V

hence

potential difference across R5 = V5 = V - V1 = 11.8565615 V

current through R5, i5 = V5/R5 = 1.69379 A

current through R2 = i2 = i1 - i5 = 1.4491 A

potential difference across R2, V2 = i2*R2 = 8.694632 V

potential difference across R3 , R4, V3 = V5 - V2 = 3.1619285 V

hence current through R3, i3 = V3/R3 = 0.39524106 A

current through R4, i4 = V3/R4 = 1.053976179 A

Q2. C = 12.2 uF

Q = 42.5 uC

R = 1850 ohms

q = 21.2 uC

hence

q = Qe^(-t/RC)

21.2/42.5 = e^(-t/1850*12.2*10^-6)

t = 0.0156975 s

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