Question 1 [1.6 pts] Which one of the following statements is correct? Question

Question

Question 1 [1.6 pts] Which one of the following statements is correct?

Question 2 [1.6 pts] Which one of the following statements is correct?

Question 3 [1.6 pts] What is the identify of compound C?*
Question 4 [1.6 pts] What is the identify of compound D?*
Question 5 [1.6 pts] What sugar is the C-5 epimer of L-talose?*

Question 6 [1.6 pts] This is a matching question. You will be asked to provide the appropriate attributes – alpha orbeta, first number, second number - for the glycosidic linkage in compound E.

Question 7 [1.6 pts] This is a matching question regarding Figure #1.You will be asked to provide the configurations of carbons a, b and c.

OH OH OH OH HO OH Question 1 [1.6 pts] Which one of the following statements is correct? O Compound A is a D sugar O Compound A is an L sugar Question 2 [1.6 pts] Which one of the following statements is correct? O Compound B is a D sugar O Compound B is an L sugar is a sug an af thetolowing statements s

Explanation / Answer

1.D and L designations are based on configuration of anomeric carbon of the structure.when there are more chiral centres D or L are based on the farthest carbon from aldehyde or ketose group.D and L are mirror images of one another.

According to fisher projections,

A-L sugar.because OH group attached to anomeric C lies upwards,so that in fisher projection it lies in left hand side.

2.same explanation as above.

B-L sugar.(pyranose form)

3.alpha-D-talopyranose

4.this is in alpha furanose form because anomeric OH lies downward.

5.C-5 epimer means,OH group in C5 position which is in left hand side in L-talose,can be drawn in right hand side for C-5 epimer.

6.beta linkage because beta Anomeric OH of first compound links with the H in another plane of the second compound.

Beta-1,3-linkage

7.a and b are D forms.,because OH groups lies in the right hand side..and c is a L form as the OH group lies in the left hand side.

8.reducing sugar.because of the presence of free OH at the anomeric position of second compound linked.

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