Figure 22-3 10 cm 45 6.0 cm 6.0 cm 45° 45° 10 cm wire in the shape of an \"M\" l

Question

Figure 22-3 10 cm 45 6.0 cm 6.0 cm 45° 45° 10 cm wire in the shape of an "M" lies in the plane of the paper. It carries a current of 2.0 A, flowing 17) rom A to E. It is placed in a uniform magnetic field of 0.85 T in the same plane, directed as shown 17) A on the right side of Figure 22-3. The figure indicates the dimensions of the wire. What is the A) 0.12 N perpendicular out of the page C) 0.20 N perpendicular out of the page B) 0.20 N perpendicular into the page D) 0.12 N perpendicular into the page

Explanation / Answer

Force is given by:

F = ILB sin(th)

For section AB of the given wire:

F = 2*0.1*0.85*cos45

= 0.12 N

The force is perpendicular and by right palm rule it is out of the page.

Thus the correct option is (A)

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