,atl 73%. 07:07 oncapaT.hep.uprm.edu/res, 90 Messages Courses Help Logout 68 Fis

Question

,atl 73%. 07:07 oncapaT.hep.uprm.edu/res, 90 Messages Courses Help Logout 68 Fisica II Febrero2018 ing3172 Main Menu Contents Grades Course Contents » .. »ingSet03 » 18.27 Electric Timer Notes Evaluate Feedback Print Info 18.27 Electric Field: Concept of a Field Revisited Points:1 What is the magnitude and direction of an electric field that exerts a 1.90x105 N upward force on a -2.30 uC charge? Direction Downward Upward To the right To the left Submit Answer Tries 0/5 his discussion is closed Send Feedback

Explanation / Answer

use the expression -

F = Eq

put the values -

1.90 x 10^-5 = E x (-2.30 x 10^-6)

=> E = (1.90 x 10^-5) / (-2.30 x 10^-6) = - 8.26 N/m

So, the magnitude of the electric field, E = 8.26 N/m

And its direction is towards DOWNWARD.

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