A 1,160-kg car traveling initially with a speed of 25.0 m/s in an easterly direc

Question

A 1,160-kg car traveling initially with a speed of 25.0 m/s in an easterly direction crashes into the rear end of a 9,900g right after the collision is 18.0 m/s to the east truck moving in the same direction at 20.0 m's (oe fgure below) The velcity of th +25.0 m/s +200 m/s 18.0m/s Before Athe a) What is the velocity of the truck right after the collision? (Round your answer to at least three decimal places) 20 82 m/'s (east How much mechanical energy is lost in the collision Account for this loss in energy

Explanation / Answer

a)

Using law of conservation of momentum

initial momentum of the system Final momentum of the system

(1160*25)+(9900*20) = (1160*18) + (9900*v)

v = 20.82 m/s

b) lost in mechanical energy is Ef-Ei = (0.5*1160*18^2)+(0.5*9900*20.82^2)-(0.5*1160*25^2)-(0.5*9900*20^2)

Ef-Ei = -8891.62 J

negative sign shows that lost in mechanical energy

c) During collision,energy is transformed From one body to another body,during this tranformation some energy will lost due to frictional Forces and due to some dissipative Forces

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