A 1 kg block slides up a frictionless inclined plane. the angle of the incline i

Question

A 1 kg block slides up a frictionless inclined plane. the angle of the incline is 30 degrees. the initial velocity at the bottom of the incline is 2.8 m/s. Use conservation of energy to answer the following questions: What is the kinetic energy of the block at the bottom of the incline? What is the potential energy of the block at the bottom of the incline? Take y*0 at the bottom. As the block slides up the plane, the potential energy is_while the kinetic energy is until it reaches the maximum height, h, above the original level reached by the block is closest to the maximum distance, L, reached along the incline from the starting point is closet to This frictionless system is best described as a) non conservative >> b) conservative

Explanation / Answer

1) KE = 1/2*m *v2   = 0.5*1*2.82   = 3.9 J

2 ) 0

3 ) b

4 ) c   

anergy conservation KE = m*g*h = 3.92

h = 3.92 / mg = 3.92/ 1*9.8 = 0.4 m

5) 0.4 / sin ( 30 ) = 0.8 m

6 ) b

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