006 (part 1 of 2) 10.0 points A capacitor is constructed from two square metal p

Question

006 (part 1 of 2) 10.0 points A capacitor is constructed from two square metal plates. A dielectric K = 208 fills the upper half of the capacitor and a dielectric K = 9.8 fills the lower half of the capacitor. Neglect edge effects. dielectric 2.68-t- constant top dielectric bottom 0.6 mm Calculate the capacitance C of the device. Answer in units of pF. 007 (part 2 of 2) 10.0 points What is the ratio op of plate charge in bottom the top-half region to that in the bottom-half region. exact answer. don't round

Explanation / Answer

According to the concept of the capacitance

Basing on the fig

The effective capacitance =>Ceq=€A/d*(2K1K2/K1+K2)

Given that

Dielectric constant K1=2.68

Dielectric constant K2=9.8

Area A=0.6*0.13*10^-3=7.8*10^-5 m^2

Distance d=6*10^-4 m

Now we find the equivalent capacitance

Ceq=(8.85*10^-12*7.8*10^-5/6*10^-4)*(2*2.68*9.8/2.68+9.8)

=4.84 pF

Now we find the ratio of the charges

Qtop/Qbottom ={VCtop/V*Cbottom)

Qtop/Qbottom =Ctop/Cbottom

=(2K1€A/d)/(2K2€A/d)

=K1/K2

=2.68/9.8=0.2735

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