A straight, vertical wire carries a current of 1.20 A downward in a region betwe

Question

A straight, vertical wire carries a current of 1.20 A downward in a region between the poles of a large superconducting electromagnet, where the magnetic field has magnitude B = 0.693 1 and is horizontal, what are the magnitude and direction of the magnetic torce on a 1.00 cm section of the wire that is in this uniform magnetic field in the tollowing scenarios? (a) the magnetic field direction is east N -Direction (b) the magnetic field direction is south NI-Direction.. (c) the magnetic field direction is 30.0° south of west N -Direction-

Explanation / Answer

a) magnetic force acting on current carrying wire,

F = B*I*L*sin(theta)

= 0.693*1.2*0.01*sin(90)

= 0.0832 N

direction : South

b) magnetic force acting on current carrying wire,

F = B*I*L*sin(theta)

= 0.693*1.2*0.01*sin(90)

= 0.0832 N

direction : West

c) magnetic force acting on current carrying wire,

F = B*I*L*sin(theta)

= 0.693*1.2*0.01*sin(90)

= 0.0832 N

direction : 30 degrees West of North or 60 degrees North of West

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