oo VIVA LTE @ 45% 8:36 PM session.masteringphysics.com Exercise 22.2 2 Mastering

Question

oo VIVA LTE @ 45% 8:36 PM session.masteringphysics.com Exercise 22.2 2 MasteringPhysics A point charge of-3.00 C is located in the center of a spherical cavity of radius 6.80 cm inside an insulating spherical charged solid. The charge density in the solid is 7.35 × 10-4 C/m2. Part A Calculate the magnitude of the electric field inside the solid at a distance of 9.30 cm from the center of the cavity. Express your answer with the appropriate units. B-1 Value Units Submit Request Answer Part B Find the direction of this electric field. radially outward radially inward Submit Request Answer

Explanation / Answer

Given,

Q = -3 x 10^-6 C ; r = 6.8 cm ; rho = 7.35 x 10^-4

r = 9.3 cm

volume of the cavity will be:

V = 4/3 pi (R^3 - r^3)

the charge on the cavity will be:

Q = rho V = rho 4/3 pi (R^3 - r^3)

Q = 7.35 x 10^-4 x 4/3 x 3.14 (0.093^3 - 0.068^3) = 1.51 x 10^-6 C

Qtot = -3 x 10^-6 + 1.51 x 10^-6 = -1.49 x 10^-6 C

E = k Qtot/d^2

E = 9 x 10^9 x 1.49 x 10^-6/0.093^2 = 1.55 x 10^6 N/C

Hence, E = 1.55 x 10^6 N/C

Radially outwards

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