apt Sapling Learning macmilan learning experiment is performed on an unknown mat
ID: 1580968 • Letter: A
Question
apt Sapling Learning macmilan learning experiment is performed on an unknown material and produces the following heat curve. The temperature of the material is shown as a function of heat added. If the sample of material has a mass of m-9.20 g, calculate the specific heat when this material is a solid, c, and when it is liquid, q. (Please see the hint panel for the explicit temperatures of fusion and vaporization, do not try to approximate from the graph.) Temperature (Celsius) 2i0 500 A530 400 350 300 2s0 200 150 100 42.750 171 819 1430 2870 Heat (J) Number NumberExplanation / Answer
Accoriding to the given problem,
Usng the concept of heat transfer,
Q = m*C*(Tf - Ti)
if m = 9.20 g then
We know that, slope = Change in heat / (change in T)
slope = (819-171)/(237 - 45.2)
slope = 3.3785 J/°C
But we need per unit mass
3.3785 J/°C * 1/(9.20g) = 0.3672 J/g°C
Finally,
choose
slope2 = Q2/(Tf-Ti) = (2870-1430)/(479-237)
slop2 = 5.950 J/gC
per unit mas
5.490/9.2 = 0.6468J/goC for liquid.
I hope you understood the problem, If yes rate me!! or else comment for a better solution.
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