Question 9 Please (-) WebAssign-PHY 213 SP2018. × y Homework #5 Chegg Study l Gu

Question

Question 9 Please

(-) WebAssign-PHY 213 SP2018. × y Homework #5 Chegg Study l Guided Solutio × ( G how to zoom in on mac-Goo × × Secure l https://www.webassign.net/web/Student/Assignment-Responses/last?dep.18310153 Need Help? Read It 9. + -2 points SerCP11 19.P.026. My Notes Ask Your T A wire having mass per unit length of 0.520 g/cm carries a 2.40 A current horizontally to the south. What are the direction and magnitude of the minimum magnetic field needed to lift this wire vertically upward? magnitude direction Need Help? Read It Submit Answer Save Progress Practice Another Version 10. -12 points SerCP11 19.P.030. My Notes Ask Your T Mass m = 1.15 kg is suspended vertically at rest by an insulating string connected to a circuit partially immersed in a magnetic field as in the figure below. The magnetic field has magnitude B 3.60 T and the length0.430 m. xXXXXxxX xXXXXXxX

Explanation / Answer

to lift vertically upward

wire weight should be balanced by the magnetic force

m*g = i*l*B

B = (m/l)*(g/i)

given that m/l = 0.52 g/cm = 0.052 kg/m

then B = (0.052)*(9.8/2.4) = 0.212 T

direction should be east

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