how do I find the motion information? he lift on the balloon due to the buovant

Question

how do I find the motion information?

he lift on the balloon due to the buovant force is constant. The student begins mis relative to the ground. The balloon's upward speed is decreased 4 70 kg sudent is hanging from a 280 kg helium balloon. The ballos0 helium balloon. The balloon is rising at a constant speed of 8.0 the groumd 2 to climb up the rope at a speed of 15 as the student climbs. Free-Body Diagrams Motion DiagramMotion Information student Event 1: Event 2: Object: Pi = 12 balloon Object: J12 = Mathematical Analysis

Explanation / Answer

For the balloon

Initial momentum P1 = 280 X 8 = 2240 Kgm/s

let the final velocity be v , final momentum P2 = 280 v

For the student

Initial momentum P1 = 70 X 8 = 560 Kgm/s

final momentum P2 = 70 X 15 = 1050 Kgm/s

Initial momentum = final momentum

2240 + 560 = 280 v + 1050

v = 6.25 m/s

the baloons' new speed is 6.25 m/s

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