While visiting the Albert Michelson exhibit at clark university, you notice that
ID: 1580337 • Letter: W
Question
While visiting the Albert Michelson exhibit at clark university, you notice that a chandelier (which looks remarkably like a simple pendulum) swings back-and-forth in the breeze once every T = 6.2 seconds. A). Calculate the frequency of oscillation in hertz of the chandellier. B). Calculate the angular frequency w of the chandelier in radians/second. C). Determine the length L in meters of the chandelier. D). That evening, while hanging out in J.J.Thompson's house O' blues you notice that( coincidentally) there is a chandelier identical in every way to the one at the michelson exhibit except this one swings back-and-forth 0.01 seconds slower, so the period is T + 0.01 seconds. Determine the acceleration due to gravity in m/s^2 at the club. While visiting the Albert Michelson exhibit at clark university, you notice that a chandelier (which looks remarkably like a simple pendulum) swings back-and-forth in the breeze once every T = 6.2 seconds. A). Calculate the frequency of oscillation in hertz of the chandellier. B). Calculate the angular frequency w of the chandelier in radians/second. C). Determine the length L in meters of the chandelier. D). That evening, while hanging out in J.J.Thompson's house O' blues you notice that( coincidentally) there is a chandelier identical in every way to the one at the michelson exhibit except this one swings back-and-forth 0.01 seconds slower, so the period is T + 0.01 seconds. Determine the acceleration due to gravity in m/s^2 at the club. A). Calculate the frequency of oscillation in hertz of the chandellier. B). Calculate the angular frequency w of the chandelier in radians/second. C). Determine the length L in meters of the chandelier. D). That evening, while hanging out in J.J.Thompson's house O' blues you notice that( coincidentally) there is a chandelier identical in every way to the one at the michelson exhibit except this one swings back-and-forth 0.01 seconds slower, so the period is T + 0.01 seconds. Determine the acceleration due to gravity in m/s^2 at the club.Explanation / Answer
A) frequency = 1/ T = 1/ 6.2 = 0.161 Hz
B) Angular Frequency = = 2T = 2 (6.2) = 38.95 rad/s
C) T = 2 / = 2 (L/g)
L = ( T / 2 )^2 * g = ( 6.2 / 2 )^2 * 9.8 = 929.5 m
D) let acceleration due to gravity at new place be g'
new T' = 2 (L/g')
6.2+0.01 = 2 (L/g')
6.21 = 2 ( 929.5 / g' )
(6.21 / 2 )^2 = 929.5 / g'
g' = 929.5 / (6.21 / 2 )^2 = 9.76 m/s^2
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