A passenger rushing to catch a plane at the airport walks on a moving sidewalk a

Question

A passenger rushing to catch a plane at the airport walks on a moving sidewalk at a speed of 2.5 km/h relative to the sidewalk in the direction that the sidewalk is moving. The sidewalk is 100 m long and moves with a steady velocity of 2.0 km/h. -How long (in s) does it take for the passenger to get from one end of the sidewalk to the other, that i ­to cover the 100 m? -How much time does the passenger save by taking the moving sidewalk instead of just walking beside it? -Through what distance does the passenger walk relative to the moving sidewalk? -If the passenger's stride is 75 cm, how many steps are taken in going from one end of the moving sidewalk to the other?

Explanation / Answer

a) Using the equation,

s = ut+ 0.5*at^2

as a = 0

so, t = s/u = 100/((2.5+2)/3.6) = 80 s

b) s' = 100/((2.5/3.6)= 144 s

So, time saved = 144 - 80 = 64 s

c) distance = (2.5/3.6)* 80 = 55.56 m

d) number of steps = 55.56/0.75 = 74 steps

Please rate my answer, good luck...

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