A block of ice and a rubber ball of identical mass are released from the top of

Question

A block of ice and a rubber ball of identical mass are released from the top of an inclined plane and allowed to descend under the influence of gravity. Assuming that the block of ice slides without friction and that the rubber ball rolls without slipping, which object will be the first to reach the bottom of the incline if the two objects are released from the same height and at the same instant? The ball will reach the bottom of the incline first O The ice will reach the bottom of the incline first O They will reach the bottom of the incline at the same instant. O There is not enough information to answer the question.

Explanation / Answer

For ball:

along the incline, Applying Fnet = m a

m g sin(theta) - f = m a ..... (i)

and torque = I alpha

f r = (2 m r^2 / 5)(a/r)

f = 0.4 m a

putting in (i)

m g sin(theta) - 0.4m a = m a

a = g sin(theta) /1.4

for block, m g sin(theta) = m a

a = g sin(theta)

acceleration of block is greater hence it will take less time.

Ans: The ice will reach the bottom of incline first.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.