A block is resting on a ramp as shown in the figure below. You can change the in

Question

A block is resting on a ramp as shown in the figure below. You can change the inclination angle 0 by raising one end of the ramp. The block has a mass m 9.0 kg. At the interface between the ramp and the block, the coefficient of static friction is us 0.50, and the coefficient of kinetic friction is Auk 0.450 t slip? Note that you can enter your answer in either radians or degrees, as long as you include the f you raise the end of the ramp very slowly so that you can assume a 0 for the block, at what angle w correct units: rad" or "deg" (without the quotes 4.6365x10 rad 1pts You are correct. Previous Tries Your receipt no s 163-3872 (2 If it slips at that angle, what will the magnitude of its acceleration be? a 4.3872x 10 m/s 2 1pts You are correct. Previous Tries Your receipt no s 163-9915 2 How long does it take from the time it slips to travel a distance d 0.95 m down the ramp? 2.0811 s 1pts You are correct. Previous Tries Your receipt no s 163-6031 2 Now let's go back and consider the static situation again. Let the angle be the angle you calculated in the first part of this problem, Assume that a horizontal force directed to the right is applied to the block. This horizontal force F as a magnitude of 66.218 Newtons. Calculate the force due to static friction, fs for this new situation, assuming that the block does not slip Make your answer positive if fs is directed up the plane, and negative if fs is directed down the plane. pts

Explanation / Answer

from us = tan theta = = 0.5

theta = 26.56 deg

so

use mg sin theta = 9 * 9.8 sin 26.56 = 39.43 N

so
fs = 39.43 7 - 66.21 8 cos 26.56

fs = -19.79 N

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