at tho answer. 1) A proton accelerates from rest in a uniform electric field of
ID: 1576890 • Letter: A
Question
at tho answer. 1) A proton accelerates from rest in a uniform electric field of 640 N/C. At so me later time, its speed is 1.20 x 10s m/s. (a) Find the magnitude of the acceleration of the proton. (b) How long does it take the proton to reach this speed? (c) How far has it moved in that interval? (d) What is its kinetic energy at the later time? 2) Given a 2.50-uF capacitor, a 6.25 F capacitor, and a 6.00-V battery, find the charge on eac capacitor if you connect them (a) in series across the battery and (b) in parallel across the battery Copyright Cengage Leaming Powered by CogneroExplanation / Answer
mp = 1.673 x 10^-27 kg
e = 1.602 x 10^-19 C
F = qE = ma
a)
a = qE / m
a = (1.602 x 10^-19 C x 640 N/C) / (1.673 x 10^-27 kg)
a = 6.1284 x 10^10 m/s^2
b)
using, v = u + at with v = 1.20 x 10^6 m/s and u = 0
t = v/a
t = (1.20 x 10^6) / (6.1284 x 10^10)
t = 1.96 x 10^-5 sec
c)
v^2 = u^2 + 2as
here, s = v^2 / 2a
s = (1.44 x 10^12) / (12.257 x 10^10)
s = 11.75 m
d)
kE = 1/2mv^2
kE = 0.5 x 1.673 x 10^-27 x 1.44 x 10^12
kE = 1.2046 x 10^-15 N.m
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