www.sX ng.ca/ibiscms/mod/ ibis/view.php?id=279553 Jump to... 1/31/2018 11:55 PM
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www.sX ng.ca/ibiscms/mod/ ibis/view.php?id=279553 Jump to... 1/31/2018 11:55 PM 32.7/100 Print Available From: Due Date: Points Possible: Grade Category Description: Sapling Leerning resistors are out of three different materials and have r cross-section of radius 1.61 mra. Resistor 2 has a square cross section with a side different (but uniform) cross-sections esistor 1 has a length of 1.37 mm. The third resistor's cross-section is a right t sh of the resistors are 0.838 cm in length. Use the with two sides of 3.56 mm as table of resistivities to calculate the Material 19.27 x 10°.m 0.294 -m | 799 x 106 -m Material 2 You can check You can view so give up on any Material 3 until you get it r You lose 5% of t answer in your o 1.61 mm eT R, O Help With This Oweb Help & Vid Technical SuppExplanation / Answer
R = rho L / A
R1 = (9.27 x 10^-3) (0.838 x 10^-2) / (pi (1.61 x 10^-3)^2)
R1 = 9.54 ohm ......Ans
R2 = (0.294) (0.838 x 10^-2) / (1.37 x 10^-3)^2
R2 = 1312.7 Ohm ......Ans
A3 = (3.56 x 10^-3)/2 =6.3368 x 10^-6 m^2
R3 = (7.99 s 10^-6)(0.838 x 10^-2) / (6.3368 x 10^-6)
R3 = 0.0106 ohm ......Ans
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