wwutamus 2017 P201. Wook lgraded) Problem 5.41 Problem 5.41 You are working for
ID: 1531113 • Letter: W
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wwutamus 2017 P201. Wook lgraded) Problem 5.41 Problem 5.41 You are working for a shipping oompany Your job is to stand al he bottom of B2 m long ramp that is inclined at 30 above the horizontal. You grab packages off a conveyor belt and propel then up the ramp. The coeficient of kinetic friction between he packages and the ramp is Part A speed do you need to gwe a package at the botom of the ramp o tatt has zero speed at the top the ramp? Express your answer using two significant figures Subm My Answers Give Up Part B Your coworker is supposed grab the packages as they amive at the of the ramp But she misses one and Rslides back down What is its speed when it return to you? Express your answer using two significant figures, Submit My Answers erve up ContinueExplanation / Answer
for a mass moving up the incline plane
Fnet = m*g*sintheta + uk*m*g*costheta
from newtons law Fnet = m*a
therefore
a = g*(sintheta + uk*costheta) down the incline
a = -9.8*(sin36+0.3*cos36) = -8.13 m/s^2
if the pacakge is given a speed v up the plane, it comes to stop at the top
final speed = vf = 0
distance travelled = x = 8.2 m
from
vf^2-vi^2 = 2*a*x
0^2-v^2 = -2*8.13*8.2
v = 11.54 m/s <<--------answer
++++++++++++++++
wen the mass slides back
Fnet = m*g*sintheta - uk*m*g*costheta
from newtons law Fnet = m*a
therefore
a = g*(sintheta - uk*costheta) down the incline
a = 9.8*(sin36-0.3*cos36) = 3.38 m/s^2
initial speed on the top = vi = 0
final speed = vf = v
distance travelled = x = 8.2 m
from
vf^2-vi^2 = 2*a*x
v^2-0^2 = 2*3.38*8.2
v = 7.44 m/s <<--------answer
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