1731/2018 11:59 PM A 59.1/100 1/28/2018 12:15 PM Gradebool PrintCalculatorPeriod

Question

1731/2018 11:59 PM A 59.1/100 1/28/2018 12:15 PM Gradebool PrintCalculatorPeriodic Table Question 24 of 31 rect Sapling Learning Map An undiscovered planet, many lightyears from Earth, has one moon in a periodic orbit. This moon takes 1710 x 103 seconds about 2.0 ×10 days on average to complete one nearly aralar revolt on around the unnamed planet. If the distance from the center of the moon to the surface of the planet is 285.0 x10 m and the planet has a radius of 3.60 x 10% m, calculate the moon's radial acceleration. Number .-134.9 × 104 | m/s2 Incorrect.

Explanation / Answer

Angular speed,

w = 2*pi / T

w = 2*3.14 / (1710*10^3)

w = 3.67*10^(-6) rad/s

Moon's radial acceleration,

a = w^2*r

a = (3.67*10^(-6) )^2 * (285*10^6 + 3.6*10^6)

a = 3.89*10^(-3) rad/s^2

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