Balancing a Stick Points:3 The figure below is a long, massless stick with evenl
ID: 1574294 • Letter: B
Question
Balancing a Stick Points:3 The figure below is a long, massless stick with evenly spaced marks. The distance between two adjacent marks is 6.10 cm. In each of the following problems a pivot will be placed at a point on the stick. The pivot will hold that point fixed, but allow the stick to rotate. You will be finding conditions that will keep the stick in static equilibrium given different forces. All forces will be applied to the stick perpendicular to the length of the stick. A pivot is placed at Point A and a force of 28.0 N is directed downward perpendicular to the stick at Point H. What is the magnitude and direction of the force which must be applied at point L in order to obtain static equilibrium? Upward Downward Submit Answer Tries 0/50 A pivot is placed at Point G and a force of 26.0 N is directed downward perpendicular to the stick at Point F. What is the magnitude and direction of the force which must be applied at point K in order to obtain static equilibrium? Upward Downward Submit Answer Tries 0/50 A pivot is placed at Point A and a force of 26.0 N is directed downward perpendicular to the stick at Point E. One at a time, each of the following 3 forces are applied to the stick in the manner described. Where must these forces be applied in order to achieve static equilibrium? If the is no point that will work within reason, select the option None. A force of 26.0 N directed downward perpendicular to the stick. A force of 9.5 N directed upward perpendicular to the stick. A force of 20.8 N directed upward perpendicular to the stick. Submit Answer Tries 0/50Explanation / Answer
A]
The net torque on the system should be zero
so, taking moments about point A,
3(0.061)(28) = 4(0.061)R
=> R = 21 N
This should be the magnitude of DOWNWARD force at L.
B] Using the same concept, the net torque about G should be zero.
8(0.061)(26) = 5(0.061)P
=> P = 41.6 N
This should be the magnitude of UPWARDS force at H.
C] A downward force of 26 N is applied 4 units to the right of A [at E]. So, to counteract this, an equal downward force of 26 N must be applied 4 units to the left of A which is at L.
For the other two forces, the net force in the vertical direction is not zero and so no position for either of the forces will give static equilibrium. Therefore, the answer is None for 9.5 N and 20.8 N.
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