Activity 2701-Winter-01-19-2018, Last Name, First Initial 3) The car running at

Question

Activity 2701-Winter-01-19-2018, Last Name, First Initial 3) The car running at 30m/s (67 mi/hr) has to stop to avoid collision. It took 3 seconds between applying the break and stopping the car. (Hint: V-v, + a t; d-d: + vt+ ½ at) a) What was the acceleration of the car? b) How many meters the car took to stop. 4) If a different car with anti-lock brake took 5meters to stop, from 30m/s to Om/s. a) What is the acceleration (deceleration) of the car? (Hint: use the two motion equation and form equation without t(time)) v, = y + a * t t = vrav, ; substitute t in the equation d,-d, + y * t You should get, -y? + 2 * a * (d,-4) Vr-V * a * t2

Explanation / Answer

a) acceleration a = vf-vi/t

a = 0-30/3 = -30/3 = -10 m/s^2

b) d = 30*3-1/2*10*3^2 = 90-45 = 45 m

4) vf^2-vi^2 = 2ad

a = 0-30^2/2*5 = -900/10 = -90 m/s^2

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