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Please answer all parts (33%) Problem 3: Suppose that we have two hanging rods o

ID: 1573806 • Letter: P

Question

Please answer all parts

(33%) Problem 3: Suppose that we have two hanging rods of the same length 2.2 m. However, their cross sections are a circle with radius 2.5 mm and a square with sides (2.2.5) mm. Both rods have the same Young's Modulus of 2.5 x 101 N/m2 50% Part (a) If we attach a heavy ball of mass 24 kg at the end of the first rod (the one with the circular cross section), how much would it stretch in millimeters? Grade Summary Deductions Potential circle 0% 100% Submissior Attempts remaining: 4 ns cos) cotanasin) sinO acos) acotansinh(O hcotanh( % per attempt) detailed view atan)a coshO tan END egrees Radians CLEAR Submit I give up! Hints:-for a 0% deduction. Hints remaining: Feedback: 0% deduction per feedback. 50% Part (b) If we attach the same ball of mass 24 kg at the end of the second rod (the one with the square cross section), how much would it stretch in millimeters?

Explanation / Answer

a) use, Y = Stress/strain

Starin = Strees/Y

delta_L/L = (m*g/A)/Y

delta_L = m*g*L/(A*Y)

= 24*9.8*2.2/(pi*0.0025^2*2.5*10^11)

= 1.05*10^-4 m

b)

use, Y = Stress/strain

Starin = Strees/Y

delta_L/L = (m*g/A)/Y

delta_L = m*g*L/(A*Y)

= 24*9.8*2.2/((2*0.0025)^2*2.5*10^11)

= 8.28*10^-5 m

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