A parallel plate capacitor is connected to a battery that maintains a constant p

Question

A parallel plate capacitor is connected to a battery that maintains a constant potential difference between the plates. If the plates are pulled away from each other, increasing their separation, what happens to the amount of charge on the plates?

The amount of the charge decreases, because the capacitance increases.

Nothing happens; the amount of charge stays the same.

The amount of the charge increases, because the capacitance increases.

The amount of the charge increases, because the capacitance decreases.

The amount of the charge decreases, because the capacitance decreases.

Explanation / Answer

We know that

Q = C*V

If V = potential difference between plates is constant than Charge on plates is directly proportional to capacitance.

Now we know that

C = e0*A/d

if d = distance between plates is increased than capacitance will decrease Since C is inversely proportional to d.

So the amount of charge decreases because the capacitance decreases.

Correct option is E.

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