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Figure 1 Figure 2 Figure 3 Figure 4 A concave lens refracts parallel rays in suc

ID: 1571325 • Letter: F

Question

Figure 1

Figure 2

Figure 3

Figure 4

A concave lens refracts parallel rays in such a way that they are bent away from the axis of the lens. For this reason, a concave lens is referred to as a diverging lens.

Part A

Consider the following diagrams, where F represents the focal point of a concave lens. In these diagrams, the image formed by the lens is obtained using the ray tracing technique. Which diagrams are accurate?(Figure 1) (Figure 2) (Figure 3) (Figure 4)

Type A if you think that only diagram A is correct, type AB if you think that only diagrams A and B are correct, and so on.

Part B

If the focal length of the concave lens is -7.50 cm , at what distance do from the lens should an object be placed so that its image is formed 3.70 cm from the lens?

Part C

What is the magnification m produced by the concave lens described in Part B?

Part D

Where should the object be moved to have a larger magnification?

(1) The object should be moved closer to the lens.

(1) The object should be moved closer to the lens.

(2) The object should be moved farther from the lens. (3) The object should be moved to the focal point of the lens. (4) The object should not be moved closer to the lens than the focal point. Object Concave lens Image

Explanation / Answer

A parallel ray deviates from its original path and diverges

a ray appear to passing through Focal point ,it passes parallel to the principle axis

A ray passing through the pole ( center of the lens) passes undeflectedly

so the answer for part A) is AC


part B)

USing lens equation

1/f = 1/do + 1/di


-1/7.5 = (1/do) + (-1/3.7)


di is negative for virtual image

do = 7.30 cm is the required object distance

PArt C)

magnification is m = -di/do = 3.7/7.3 = 0.506

part D)

to get larger magnification,the size of the image should be increased

to happen this the object should be moved closed to focal point towards the lens

so the answer is 1) the object should be moved closer to the lens

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