2.2 mol of monatomic gas A initially has 4500 J of thermal energy. It interacts

Question

2.2 mol of monatomic gas A initially has 4500 J of thermal energy. It interacts with 2.9 mol of monatomic gas B, which initially has 8100 J of thermal energy. You may want to review ( pages 559 - 561) .

Part A Which gas has the higher initial temperature? Which gas has the higher initial temperature? Gas A. Gas B.

Part B What is the final thermal energy of the gas A? Express your answer to two significant figures and include the appropriate units. Ef =

Part C

What is the final thermal energy of the gas B?

Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

(a)Thermal Energy of the gas (E) = (3/2)nRT
where n is no. of mole , R is gas constant and T is the temperature
EA = (3/2)*2.2*8.315*TA
(3/2)*2.2*8.315*TA = 4500
TA = 163.997 K
EB = (3/2)*2.9*8.315*TB
(3/2)*2.9*8.315*TB = 8100
TB = 223.94 K
Hence the gas B has the higher temperature
(b) final temperature of the gas
T =( nATA + nBTB ) /(nA+nB) = (2.2*163.997 + 2.9*223.94) /(2.2+2.9) = 198.08 K
Final temperature of the gas A and B = 198.08 K
Final energy of the gas A = (3/2)nRT = (3/2)*2.2*8.315*198.08 = 5435.277 J
(c) Final energy of the gas B = (3/2)nRT = (3/2)*2.9*8.315*198.08 = 7164.603 J

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