How could^96 _40 Zr decay to the same daughter nucleus without violating any con

Question

How could^96 _40 Zr decay to the same daughter nucleus without violating any conservation laws? If the^96 _40 Zr would undergo 2 beta decays simultaneously, and so emit 2 muon neutrinos, then it could decay to^96 _42 Mo without violating any conservation laws. If the^96 _40 Zr would undergo 2 beta decays simultaneously, and so emit 2 muon anti-neutrinos, then it could decay to _96 _42Mo without violating any conservation laws. If the^96 _40 Zr would undergo 2 beta decays simultaneously, and so emit 2 electron neutrinos, then it could decay to^96 _42Mo without violating any conservation laws. If the^96 _40 Zr would undergo 2 beta decays simultaneously, and so emit 2 electron anti-neutrinos, then it could decay to^96 _42Mo without violating any conservation laws.

Explanation / Answer

beta decay  is a type of radioactive decay in which a beta ray (fast energetic electron or positron), and a neutrino are emitted from an atomic nucleus. example- beta decay of a neutron transforms it into a proton by the emission of an electron, or contrary a proton is converted into a neutron by emission of a positron (positron emission), thus changing the nuclide type. Neither the beta particle nor its associated neutrino exist within the nucleus prior to beta decay, but are created in the decay process.

So option C is correct in my opinion.

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