Uniformly accelerated motion is when velocity changes at a constant rate in time

Question

Uniformly accelerated motion is when velocity changes at a constant rate in time, In summary, the law of motion in this case is: x(t) = x_0 + v_0 times t + 1/2 times a times t^2 v(t) = v_0 + a times t Positions of a cart rolling down an incline tilted at an angle alpha = 20 degree are measured at various times; they are shown in the following table. a) Calculate the velocity at each time (except the first and the last one) by using the values immediately after and before those times: V_n = X_n + 1 - X_n - 1/t_n + 1 - t_n - 1 b) calculate v/t (what are the units?), its average and its uncertainty.

Explanation / Answer

I presume you need a solution for the encirclied, a) part.

2. 0.264-0.000 / 0.400-0.000 = 0.660m/s

0.660/0.200= 3.3 m/s^2

3. 0.609-0.070/0.600-0.200=1.347 m/s

1.347/0.400=3.368m/s^2

4. 1.046-0.264/0.400= 2.615 m/s

2.615/0.600= 4.358 m/s^2

5. 1.696-0.609/0.400=4,240 m/s

4.240/0.800=5.3m/s^2

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