The lens and mirror in the figure below are separated by 1.00 m and have focal l

Question

The lens and mirror in the figure below are separated by 1.00 m and have focal lengths of +79.0 cm and 49.9 cm, respectively.
If an object is placed 1.00 m to the left of the lens, where will the final image be located? q3 = cm    Correct: Your answer is correct.
State whether the image is upright or inverted. upright. inverted. Correct: Your answer is correct.
Determine the overall magnification. Need Help? Read It The lens and mirror in the figure below are separated by 1.00 m and have focal lengths of +79.0 cm and 49.9 cm, respectively.
If an object is placed 1.00 m to the left of the lens, where will the final image be located? q3 = cm    Correct: Your answer is correct.
State whether the image is upright or inverted. upright. inverted. Correct: Your answer is correct.
Determine the overall magnification. Need Help? Read It The lens and mirror in the figure below are separated by 1.00 m and have focal lengths of +79.0 cm and 49.9 cm, respectively.
If an object is placed 1.00 m to the left of the lens, where will the final image be located? q3 = cm    Correct: Your answer is correct.
State whether the image is upright or inverted. upright. inverted. Correct: Your answer is correct.
Determine the overall magnification. Need Help? Read It

Explanation / Answer

From the given question,

object distance(u)= -1m

focal length of lens(f)=79cm=0.79m

using the relation 1/v-1/u=1/f

1/v= 1/f+1/u

v= (u+f)/uf

=(-1+0.79)/(-1)(0.79)

=0.26m

distance of first image from mirror= 1-0.26=0.74m

focal length of mirror(f2)=-0.49

from the relation, 1/u + 1/v = 1/f

1/v = 1/f - 1/u

v= (u-f)/uf

=(-0.74)-(-0.49)/(-0.74)(-0.49)

= -0.68

final image is located at 68cm left of mirror.

final Image is inverted.

overall magnification =(0.26/1)(0.68/0.74)=0.238

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