You must arrow your work to credit. Convert the following formulas to their calc

Question

You must arrow your work to credit. Convert the following formulas to their calculate equivalents: sigma_i(B_i^rightarrow middot Delta s_i^rightarrow) = mu_0^-1 enc sigma_i(B_i^rightarrow middot Delta A_i^rightarrow) = 0 Convert the following formula to its calculus equivalent: V_L = -L middot Delta i/Delat t A current is set up in an inductor, which then 'discharges' through a resistor. as shown below Substitute your result from problem 2 for the voltage across the resistor V_R = I middot R. In other words replace V_R with your expression for V_L. Rearrange your expression from problem 3 and integrate it to find an expression for the current as a function of time. Assume that the current is I_0 when t = 0. Convert the following formulas to their calculus equivalents: sigma_i(E_i^rightarrow middot Delta A_i^rightarrow) = q_enc/isin_0 V = -N middot Delta Phi/Delta t

Explanation / Answer

1A) Integral( B.dl) = mu * I (enc) ,

2) V = -L di/dt

3) -Ldi/dt - IR = 0

4) di/I = -R*dt/L

ln (I/I0) = -Rt/L

I = I0 * e^ (-Rt/L)

5) Integral(E .ds) = q (enc) / epsilon , V = - N* d(phi)/dt

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