1) a. Find the difference of the initial and the final masses for the 115B105B+n

Question

1) a. Find the difference of the initial and the final masses for the 115B105B+n. The atomic mass of 115B is 11.009306 u , the atomic mass of 105B is 10.012937 u ,the mass of neutron is 1.008665 u.

b. Is this decay possible?

2) a. Find the difference of the initial and the final masses for the 147N137N+n. The atomic mass of 147N is 14.003074 u, the atomic mass of 137N is 13.005739 u.

b. Is this decay possible?

3) a. Find the difference of the initial and the final masses for the 4019K3919K+n. The atomic mass of 4019K is 39.963999 u, the atomic mass of 3919K is 38.963707 u.

b. Is this decay possible?

Explanation / Answer

Q1.

initial mass=11.009306 u

final mass=10.012937+1.008665=11.021602 u

mass diference=final mass-initial mass=11.021602-11.009306=0.012296 u

as final mass is greater than initial, this decay is not possible.

Q2.

initial mass=14.003074 u

final mass=13.005739+1.008665= 14.014404 u

mass difference=final mass-initial mass= 14.014404 -14.003074=0.01133 u

as final mass is larger than initial mass, this decay is not possible.

Q3.

initial mass=39.963999 u

final mass=38.963707+1.008665=39.972372 u

mass difference=final mass-initial mass

=39.972372 -39.963999=0.008373 u

as final mass is greater than initial mass, this decay is not possible.

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.