Exercise 28.5 A -4.60 puC charge is moving at a constant speed of 700x105 m/s in

Question

Exercise 28.5 A -4.60 puC charge is moving at a constant speed of 700x105 m/s in the +z direction relative to a reference frame. At the instant when the point charge is at the origin, what is the magnetic-field vector it produces at the following points. Part A 0,2 z 30.500 m, y Enter your answers numerically separated by commas. Br, Bu, B, Submit My Answers Give up Part B 0, 0.500 m, z 0 Enter your answers numerically separated by commas, Ba, Bu, B. Submit My Answers Give Up Part C z 0.500 m, 0.500 m, z 0 Enter your answers numerically separated by commas

Explanation / Answer

magnetic field due to moving charge

B = (uo*q/4*pi*lrl^3)*(vxr)

part(A)

r = 0.5i

v = 7*10^5 i

Bx , By , Bz = 0 , 0 , 0

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part(B)

r = 0.5 j

magnitude of r = lrl = 0.5

B = (4*pi*10^-7*4.6*10^-6/(4*pi*0.5^3))*(7*10^5i x 0.5 j)

B = 1.29*10^-6 T k

Bx , By , Bz = 0 , 0 , 1.29*10^-6 T

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part(C)

r = 0.5i + 0.5 j

magnitude of r = lrl = sqrt(0.5^2+0.5^2) = 0.707 m

B = (4*pi*10^-7*4.6*10^-6/(4*pi*0.707^3))*(7*10^5i x (0.5i + 0.5 j))

B = 1.3*10^-12*( 3.5*10^5) k T

B = 7.65*10^-10 k T

Bx , By , Bz = 0 , 0 , 0.455*10^-6 T

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part D

r = 0.5 k

magnitude of r = lrl = 0.5 m

B = (4*pi*10^-7*4.6*10^-6/(4*pi*0.5^3))*(7*10^5i x (0.5 k))

B = 1.3*10^-12*( 3.5*10^5) -j T

B = -1.29*10^-6 j T

Bx , By , Bz = 0 , -1.29*10^-6 T , 0

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