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Exercise 28.41 Two round concentric metal wires lie on a tabletop, one inside th

ID: 1264046 • Letter: E

Question

Exercise 28.41

Two round concentric metal wires lie on a tabletop, one inside the other. The inner wire has a diameter of 24.0cm and carries a clockwise current of 10.0A , as viewed from above, and the outer wire has a diameter of 38.0cm .

Part A

What must be the direction (as viewed from above) of the current in the outer wire so that the net magnetic field due to this combination of wires is zero at the common center of the wires?

The currents direction must be clockwise

or

The currents direction must be counterclockwise

Part B

What must be the magnitude of the current in the outer wire so that the net magnetic field due to this combination of wires is zero at the common center of the wires?

Exercise 28.41

Two round concentric metal wires lie on a tabletop, one inside the other. The inner wire has a diameter of 24.0cm and carries a clockwise current of 10.0A , as viewed from above, and the outer wire has a diameter of 38.0cm .

Part A

What must be the direction (as viewed from above) of the current in the outer wire so that the net magnetic field due to this combination of wires is zero at the common center of the wires?

The currents direction must be clockwise

or

The currents direction must be counterclockwise

Part B

What must be the magnitude of the current in the outer wire so that the net magnetic field due to this combination of wires is zero at the common center of the wires?

I=   A

Explanation / Answer

PART A:

Must be COUNTERCLOCKWISE.

********************

As the magnetic field is inversely proportional to R but directly proportinal to I,

I1/R1 = I2/R2

--> I2 = I1 R2/ R1

Thus, for them to cancel at the center,

I2 = 15.83 A [ANSWER, PART B]