PHYSICS EXAM 3 Fall 2016 1. A mass is revolving in a horizontal circle. The path

Question

PHYSICS EXAM 3 Fall 2016 1. A mass is revolving in a horizontal circle. The path of the mass has a radius of 0.050 m and a period of 0.50 s. What is the linear speed of the mass in m/s? A. 0.63 B. 0.32 C. 0.21 D. 0.05 E. 3.1 2. A small ball is revolving in a horizontal circle and is held by a rigid rod. The path of the ball has a constant linear speed. The ball has a mass m 1kg. The force exerted by the rod is 0.5 N. What is the centripetal acceleration in m/sn2? a. Unknown b, 1 c, 10 d. 0.05 e. 0.5,

Explanation / Answer

1.

v = w*r

r = 0.05 m

w = 2*pi/T

w = 2*pi/0.5

So,

v = 2*pi*0.05/0.5 = 0.63 m/sec

correct option is A.

2.

Fc = m*ac

Since centripetal force is not given in the question we cannot find centripetal acceleration.

Correct option will be A.

3.

v = w*r = 10*0.1

v = 1 m/sec

correct option is A.

4.

Fc = m*v^2/R

F1/F2 = v1^2*R2/(v2^2*R1)

F1/F2 = v^2*6R/((3v)^2*2R)

F1/F2 = 6/18 = 0.33

Correct option is A.

8.

torque = I*alpha

torque = 2*3 = 6

correct option is D.

9.

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