A 0.310 m long metal bar is pulled to the left by an applied force F. The bar ri

Question

A 0.310 m long metal bar is pulled to the left by an applied force F. The bar rides on parallel metal rails connected through a 41.8 Ohm resistor, as shown in the following figure. So the apparatus makes a complete circuit. You can ignore the resistance of the bar and rails. The circuit is in a uniform 0.614 T magnetic field that is directed out of the plane of the figure. At the instant when the bar is moving to the left at 5.90 m/s, is the induced current in the circuit clockwise or counterclockwise? counterclockwise clockwise At the instant when the bar is moving to the left at 5.90 m/s, what is the rate at which the applied force is doing work on the bar?

Explanation / Answer

Part B)
B = magnetic field = 0.614 T

L = length = 0.310 m

v = speed = 5.90 m/s

R = resistance = 41.8 ohm

Power dissipated is given as

P = B2 L2 v/R

P = (0.614)2 (0.310)2 (5.90)/41.8

P = 0.00511 Watt

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