A 0.28kg object Is placed at the end to a vertical spring the unscratched (natur

Question

A 0.28kg object Is placed at the end to a vertical spring the unscratched (natural) length of the spring is 0.25m After adding the mass the final length is 0 3m What is the spring constant (in N/m)? A 0.35kg object is placed at the end of a vertical spring with a spring constant k=21.65N/m Assuming the spring is massless. what would be the period of oscillations (in s)? Assume that after completing the first activity in this lab you have this graph for the weight (force of the spring) in N as a function of change in the length in meters What is the spring constant?

Explanation / Answer

4)m = 0.28 kg ; L = 0.25 m ; L' = 0.3 m ;

x = 0.3 - 0.25 = 0.05 m

for a vertical spring

F(gravity) = F(hooks)

mg = kx => k = mg/x

k = 0.28 x 9.81 / 0.05 = 54.94 N/m

Hence, k = 54.94 N/m

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