An unpolarized beam of light (whose intensity is 150 W/m^2) strikes a polarizer

Question

An unpolarized beam of light (whose intensity is 150 W/m^2) strikes a polarizer that is rotated 40 degree from the vertical direction. What is the intensity of the light after it passes though this polarizer (in W/m^2)? A beam of light (which is vertically polarized and has an intensity of 120 W/m^2) strikes a polarizer that is rotated 50 degree from the vertical direction. What is the intensity of the light after it passes though this polarizer (in W/m^2)? An unpolarized beam of light (which has an intensity of 200 W/m^2) strikes a polarizer that is rotated 30 degree from the vertical direction. The light then passes through a second polarizer that is rotated 50 degree from the vertical direction. What is the intensity of light passing through the second polarizer (in W/m^2)? A beam of light (which is vertically polarized and has an intensity of 150 W/m^2) strikes a polarizer that is rotated 30 degree from the vertical direction. The light then passes through a second pola

Explanation / Answer

here,

the initial intensity of light , I0 = 150 W/m^2

theta = 40 degree

the intensity of light passed through the polarizer , I = I0 * ( cos(theta))^2

I = 150 * ( cos(40))^2 W/m^2

I = 88 W/m^2

the intensity of light passed through the polarizer is 88 W/m^2

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