A measure of inelasticity in a head-on collision of two objects is the coefficie
ID: 1554802 • Letter: A
Question
A measure of inelasticity in a head-on collision of two objects is the coefficient of restitution, e, defined as e = upsilon'_A - upsilon'_B/upsilon_B - upsilon_A where upsilon'_A - upsilon'_B is the relative velocity of the two objects after the collision and upsilon_B - upsilon_A is their relative velocity before it. (a) Show that e = 1 for a perfectly elastic collision, and e = 0 for a completely inelastic collision. (b) A simple method for measuring the coefficient of restitution for an object colliding with a very hard surface like steel is to drop the object onto a heavy steel plate, as shown in Fig. 7-36. Determine a formula for e in terms of the original height h' and the maximum height h' reached after one collision. Measurement of the coefficient of restitution.Explanation / Answer
a)
VA = velocity of object A before collision
V'A = velocity of object A after collision
VB = velocity of object B before collision
V'B = velocity of object B after collision
mA = mB = m = mass of each object A and B
using conservation of momentum
mA VA + mB VB = mA V'A + mB V'B
m VA + m VB = m V'A + m V'B
VA + VB = V'A + V'B
VA - V'A = - (VB - V'B) eq-1
using conservation of kinetic energy
mA V2A + mB V2B = mA V'2A + mB V'2B
V2A + V2B = V'2A + V'2B
V2A - V'2A = - (V2B - V'2B)
(VA - V'A ) (VA + V'A ) = - (VB - V'B) (VB + V'B)
using eq-1
(VA + V'A ) = (VB + V'B)
V'A - V'B = VB - VA
(V'A - V'B)/(VB - VA) = 1
e = 1
for inelastic collision
V'A = V'B= V since the two objects move together after collision at same velocity
hence
e = (V'A - V'B)/(VB - VA) = (V - V)/(VB - VA)
e = 0
b)
while the object A falls :
using conservation of energy
kinetic energy just before hitting the surface = initial potential energy at Top
(0.5) m VA2 = m g h
VA = sqrt(2gh)
similarly , for object A after collision
V'A = sqrt(2gh')
also ,
in this case , object B is the steel surface which is remains at rest all the time
hence VB = VB' = 0
e = (V'A - VB') /(VB - VA)
e = (sqrt(2gh') - 0)/(0 - (-sqrt(2gh)))
e = sqrt(h'/h)
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