Your employer asks you to build a 29-cm-long solenoid with an interior field of

Question

Your employer asks you to build a 29-cm-long solenoid with an interior field of 6.0 mT. The specifications call for a single layer of wire, wound with the coils as close together as possible. You have two spools of wire available. Wire with a #18 gauge has a diameter of 1.02 mm and has a maximum current rating of 6 A. Wire with a #26 gauge is 0.41 mm in diameter and can carry up to 1 A. Which wire should you use? #18 #26 What current will you need? Express your answer to two significant figures and include

Explanation / Answer

Lets calculate the current

B = µ ° N / L * I
µ° = 4 10^-7
N = 290mm / 1.02 = 284turns
B = 4 10^-7 * 290 / 0.29* I
6*10^-3 = 4 10^-7 * 1000 * I
I = 6* 10^-3 / 4 10^-7 * 1000= 610^-3 / 1.25610^-3= 4.778

A which is 6A

Hence , we go with a #18 gauge having a diameter of 1.02 mm

Current needed is 4.778A-------ans

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